1 class Solution { 2 public: 3     /** 4      * @param A: An integer array. 5      * @param B: An integer array. 6      * @return: a double whose format is *.5 or *.0 7      */ 8     double findMedianSortedArrays(vector
     
       A, vector
      
        B) { 9         // write your code here10         int m = A.size(), n = B.size();11         if (m > n) return findMedianSortedArrays(B, A);12         int imin = 0, imax = m, half = (m + n + 1) / 2, i, j, num1, num2;13         while (imin <= imax) {14             i = (imin + imax) / 2;15             j = half - i;16             if (j > 0 && i < m && B[j - 1] > A[i])17                 imin = i + 1;18             else if (i > 0 && j < n && A[i - 1] > B[j])19                 imax = i - 1;20             else {21                 if (!i) num1 = B[j - 1];22                 else if (!j) num1 = A[i - 1];23                 else num1 = max(A[i - 1], B[j - 1]);24                 break;25             }26         }27         if ((m + n) % 2) return num1;28         if (i == m) num2 = B[j];29         else if (j == n) num2 = A[i];30         else num2 = min(A[i], B[j]);31         return (num1 + num2) / 2.0;32     }33 };